
Jim S. answered 06/04/14
Physics (and math) are fun, really
Dalia,
A series expansion of the function f(x) at x=0 is f(0)+xf'(0)+higher order terms. f'(0) is the first derivative of f(x) at x=0.
The linear expansion is just the first two terms and f(x)=√(8+8x) so f'(x)=(1/2*8)/√(8+8x) and f(0)=4/(2*√2)=2/√2 and f(0)=2√2.
So A=f(0)=2√2 and B=f'(0)=2/√2=√2
Jim