Mark M. answered 06/18/17
Tutor
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Retired math prof. Very extensive Precalculus tutoring experience.
Let A(t) = number of bacteria in t hours
Then, A(t) = 2100ekt, and A(5) = 2459
So, 2100e5k = 2459
e5k = 1.1709524
5k = ln(1.1709524)
k = 0.1578174 ≈ 15.8%