Sava D. answered 06/15/17
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The general form of an equation for exponential cooling is
T(t) = Ta+(T0-Ta)e-kt .
Ta is the final temperature;
T0 is the initial temperature;
k is the decay constant.
We have T0=185o, Ta=75o .
We use the condition when t =30 min to find the constant k. T=150o when the time is 30 min.
T(30) = 75 + (185 - 75)e-k*30
We use the values from the problem to find k.
150 = 75 + 110e-k*30
75 = 110e-k*30
We take natural logarithm to finish the problem.
ln(75) = ln((110 e-k30))
ln(75) = ln(110) +ln(e-k30)
We use the rule that logarithm of e to the power of x is equal to x. In our case we have (-k30) instead.
ln(75) - ln(110) = -30k
k =- [ln(75) - ln(110)]/30
k =0.0127664
We use the found value of k in the formula and calculate the temperature after 60 min.
T(60) = 75 + 110 e-60*.0127664
=126o
Note, if we measure time in hours, the constant k will change, but the value of the exponent will remain the same. The answer will not change.