
Kris V. answered 06/13/17
Tutor
5
(36)
Experienced Mathematics, Physics, and Chemistry Tutor
To do this problem, you will need to
1. Find the z-scores for 70 and 120
z1 = (70 - 90)/12.6 = -1.587 ≅ -1.59
z2 = (120 - 90)12.6 = 2.38
2. Calculate the probability using a Standard Normal Distribution.
Let X be the random variable representing the life span of this snake species, then the proportion of the snakes that live between 70 and 120 is
P{70 < X ≤ 120}
= P{X ≤ 120} - P{X ≤ 70}
= P{Z ≤ 2.38} - P{Z ≤ -1.59}
= 0.9913 - 0.0559
= 0.9354 or 93.54%