Hi Amy,
I am assuming that by writing log2 9 you mean that the 2 is the base, in other words it is read log of 9 base 2.
If that is the case then you should just know this important property of logs: logc a + logc b = logc (ab)
therefore: log2 9+log2 a = log2 (9*a)
so log2 (9*a) = log2 11 and so 9*a=11 which gives you a=11/9= 1.2222