Dailia,
In general to find the inverse set y=f(x), solve for x in terms of y and then interchange x and y.
So lets let z=ex just to simplify thing some. So y=(1+z)/(1-z), solve this for z =(1-y)/(1+y) but z=ex so solving for x gives
x=Ln((1-y)/(1+y)) and interchanging y and x gives
f-1(x)=Ln((1-x)/(1+x)) where Ln is loge
Jim
Jim S.
tutor
You are correct, Dalia, I made a mistake when solving for z above my revised answer is
f-1(x)=Ln{(x-1)/(x+1)} using this as the inverse you will get for f-1(f(x))=x as it should be.
Good catch, thanks
Jim
Report
05/21/14
Dalia S.
it makes more sense now, thank you for your help jim!
Report
05/22/14
Dalia S.
05/21/14