how do you rewrite (x^-8/y^11)^ -2 without negative exponents

Question

the ^ means exponents 

Answer 1

(x^-8/y¹¹)^-2

 

Recall that x^-a = 1/x^a, so 1/y¹¹ = y^-11

 

= (x^-8*y^-11)^-2

 

(...)^-2 means to multiply each exponent in the parentheses by -2:

 

 

= x^(-8)(-2)*y^(-11)(-2)

 

= x¹⁶*y²²