area of room (-8,4) (3,4) (3-6) and (-8-6)

Question

Wants border around room which has corners drawn on coordinate grid at (-8,4), (3,4), (3,-6) and (-8-6). Need help figuring length in feet of border needed

 

Answer 1

If you plot the coordinates on the coordinate plane you would find that (-8,4) and (-8, -6) are the left 2 corners of the room/rectangle. Since the X - coordinates are the same, the length of that side would be found by finding the distance between the y - coordinates for those 2 ordered pairs. You can do this by subtracting the y-coordinates: 4-(-6) = 4+6.

 

You can find the width of the room/rectangle by doing something similar.  By plotting the coordinates you would also find that (-8,4) and (3,4) are the top 2 corners of the room/rectangle. Since the y-coordinates are the same, the width of that side would be found by finding the distance between the x-coordinates, which again can be found by subtracting them: 3-(-8)=3+8.

 

Hope this helps!