Rajesh P. answered 04/20/14
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Let probability of A winning the race = PA
Let probability of B winning the race = PB
Let probability of C winning the race = PC
Given:
PA = PB
PA = 2PC
PB = 2PC
We know that probability that either A, B, or C wins is 1
PA+PB+PC = 1
Substitute PA = 2PC and PB = 2PC in above equation
2PC + 2PC + PC = 1
5PC = 1 ...divide both sides by 5
PC = 0.2
PA = 2PC = 2x0.2 = 0.4
PB = 2PC = 2x0.2 = 0.4
a. Probability that A does not win
= 1 - probability that A wins
= 1 - PA = 1 - 0.4
= 0.6 (60% probability that A does not win)
b. Probability that B or C wins
= Probability that B wins + Probability that C wins
= PB + PC
= 0.4 + 0.2
= 0.6 (60% probability that B or C wins). This is same as the probability that A does not win.