finite math

Question

A club consisting of 6 men and 8 women will choose a committee of 5.  In how many ways can the 
committee be chosen if it must contain at least 1 man

Answer 1

Heather,

 

Here you multiply combinations where c(6,1)*c(8,4)  sets a committee where you choose one man out of six and four women out of eight. hope that helps!