Kirill Z. answered 04/15/14
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Use L'Hopital's rule :
lim (2+xe7/x)/(xarctan(x))=lim (2+xe7/x)'/(xarctan(x))'=lim (e7/x-7/x*e7/x)/(arctan(x)+x/(1+x2))=
x→∞ x→∞ x→∞
=(1-0)/(π/2+0)=2/π;
Answer: 2/π