slop 8/9, passing through (7,-3)

Question

i need aswer to this question i have try every possible ption

Answer 1

Very simple:

 

  Y = mx + b             / is the equation of the line

 

 Here you have m= 8/9  and passes through ( 7,-3)

 

 

So :  if m = 8/9 , then

 

 Y = 8/9 X + b

 

If line passes through (7, -3 ) then :

 

    -3 = 8/9 ( 7) +b

 

     b = -3 - 56/9 = - 83/9

 

   You have m & b of the equation of Y = mX +b

    The equation becomes:

  

       Y = 8/9 X - 83/9

   

Answer 2

Hello, thank you for taking the time to post your question!

The underlying equation that you want to use here is the point-slope form of a linear equation: y−y1​=m(x−x1​)

For this set of values, we have a slope m=8/9 and a point (x1​,y1​)=(7,−3).

Plugging these values into the point-slope equation gives you: y−(−3)=8/9(x−7)

Solving that algebraically for the value of “y” to put it into the slope-intercept form (y=mx+b) yields: y+3=8/9x−56/9

y=8/9x−56/9−3

y=8/9x−56/9−27/9

y=8/9x−83/9

I hope that helps you get moving in a better direction on this type of question! Feel free to reach out if you have any additional questions beyond that :)

Answer 3

Use the slope-point form for a straight line:

 

(y - y₁) = m*(x - x₁)         (point-slope form of a straight line)

 

(x₁,y₁) = (7,-3) and m = 8/9

 

y-(-3) = (8/9)(x-7)          

 

y + 3 = (8/9)x - (56/9)

 

y = (8/9)x - 9 2/9    (slope-intercept form of a straight line)