Inactive Tutor answered 04/07/14
Tutor
New to Wyzant
x=1/t --> t=1/x
replacing it to y=t/(t+1) = (1/x)/(1/x+1) = 1/1+x
The equation has horizontal asymptote at y=0 and vertical asymptote at x=-1 ...(C)
Sun K.
asked 04/07/14Inactive Tutor answered 04/07/14
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Sun K.
04/08/14