Solve trig identities.

Question

[0, 2pi) restriction.

 

sinΘcosΘ=cosΘ

Answer 1

sin(theta)*cos(theta) = cos(theta)

sin(theta)*cos(theta) - cos(theta) = 0

cos(theta)*(sin(theta) - 1) = 0

 

cos(theta) = 0 OR sin(theta) = 1

 

cos(theta) = 0: pi/2, 3pi/2

sin(theta) = 1: pi/2

 

Final answer: {pi/2, 3*pi/2}