A ball is launched at 2 meters per second (m/s) from a 10-meter tall platform. When does the object strike the ground?

Question

I am stuck on how to write an equation for this.

Answer 1

In which direction is the ball launched? Down or up? Or at an angle?

I will answer the question when the ball is going up at 2 m/sec speed.

The Earth gravity g= 9.8 m/sec².

The general formula we need to use is

 

h = -1/2 g t²+v₀t+h₀.

v₀ = 2m/sec

h₀ = 10 m.

We want h=0.

 

Here is the equation:

0 = -1/2*9.8*t²+2t+10.

 

This equation has one meaningful solution:

t = 1.64 sec.

 

If the object is thrown downward,

t=1.24 sec.