
Kemal G. answered 05/15/17
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Hi Hannah,
a1 = 1 and an=(an-1)^2 + 1
a2 = (a1-1)^2+1
= (1-1)^2+1
= 1
a3 = (a2-1)^2+1
= (1-1)^2+1
= 1
a4 = (a3-1)^2+1
= (1-1)^2+1
= 1
a5 = (a4-1)^2+1
= (1-1)^2+1
= 1
We see that all the terms of this sequence will be the same, i.e., 1.