Arthur D. answered 05/12/17
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cosAcosB=(1/2)(cos[A+B]+cos[A-B])
cos(5x)cos(3x)=(1/2)(cos[5x+3x]+cos[5x-3x])
cos(5x)cos(3x)=(1/2)(cos(8x)+cos(2x))
cos(5x)cos(3x)=0.5cos(8x)+0.5cos(2x)