Kemal G. answered 05/08/17
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Hi Couva,
The question is basically asking us to find the trigonometric functions of the angle that defines point t given in different quadrants.
I) (-√65/9, -4/9) This is in quadrant III. I will use tangent function to find the angle theta.
If the angle is theta, then (pi+theta) = tan(theta).
tan(theta) = (-4/9) / (-√65/9)
= 4 / √65
cot theta = 1/tan t = √65/4
II) (4/7, -√33/7) Find csc t.
This is in quadrant IV. csc t = 1 / sin t
Again, if the angle is theta, sin theta = -(4/7) / 1 (hypotenuse is 1)
csc theta = 1/-(4/7) = -7/4
III) (5/8, √39/8) Find tan t.
This is in quadrant I. Everything is positive here.
tan theta = (√39/8) / (5/8)
= √39/5