
Steve S. answered 03/27/14
Tutor
5
(3)
Tutoring in Precalculus, Trig, and Differential Calculus
The solid has to be a cylinder with the circle as a base.
V_cyl = B h; where B is the area of the Base.
B = pi r^2 = pi 2^2 = 4 pi square inches
"Each cross section perpendicular to a certain diameter is a square."
So h = diameter of circle = 2 r = 2*2 = 4 inches
V_cyl = 4 pi h = 4 pi 4 = 16 pi cubic inches
Answer is B, not C.