Inactive Tutor answered 03/26/14
Tutor
New to Wyzant
We have the equation for length given by L = ∫(dx/dx^2 + dy/dx^2)^(1/2) dx. This tells us that dy/dx ^2 = 16 x^6. Thus, dy/dx = 4x^3. Integrating with respect to x gives us y = x^4 +c. Substituting in the point (1,4) gives 4 = 1 + c. So c =3. Thus, y = x^4 + 3.