Find the equation of the line passing through the point P(1, -5) and perpendicular to the line 3x - 6y =7.

Question

Write the equation in slope-intercept form.

Answer 1

3x - 6y =7.

6y=3x-7

y=3/6 x-7/6

y=1/2 x -7/6

slope of a given line =1/2

slope of a perpendicular line =-2

equation of a line ,

y=mx+b......where m=slope, b=y-intercept

y=-2x+b

now line passes thru a point P(1,-5),

-5=-2*1+b

-3=b

equation of a line passes thru P(1,-5) & perpendicular to the line 3x - 6y =7 is

y=-2x-3