
Patrick D. answered 04/26/17
Tutor
5
(10)
Patrick the Math Doctor
Solving the second equation for Y:
2x + 3 = Y
substituting this into the first equation:
3x + 5 ( 2x +3) = 2
3x + 10x + 15 = 2
13x + 15 = 2
13x = -13
x = -1
Y = 2x + 3 = 2(-1) +3 = -2 + 3 = 1
Check: 1st equation: 3(-1) + 5(1) = -3 + 5 = 2
2nd equation: 2(-1) - 1 = -2 - 1 = -3
If you want to do it using elimination, multiply the first equation by -2
and the second equation by 3. Then add
-6x + -10y = -4
6x - 3y = -9
---------------------------
-13y = -13
y =1
Substituting this into the second equation:
2x - 1 = -3
2x = -2
x = -1