Hussein H.

asked • 04/23/17

evaluate the definite integral

Evaluate the definite integral
 
 a
∫−2x√(x^2+a^2) dx
-a

Kenneth S.

your first parenthesis ought to be moved toward the right so that it immediately follows the √ symbol.
 
I think that the integrand is an odd function, so the definite integral is 0 in this instance.
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04/23/17

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Herb K. answered • 07/17/17

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I agree with Kenneth S. that since the integrand is an odd function of x, and the integral, call it I, is between symmetrically placed limits, -a and a, the result should be, even without any detailed calculations, I = 0.
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