Inactive Tutor answered 04/22/17
Tutor
New to Wyzant
Set f'(x) = 0
3x2 + 14x - 7 = 0
Use the quadratic formula:
x1 = (-b - √(b2 - 4ac)) / 2a and x2 = (-b + √(b2 - 4ac)) / 2a
where:
a = 3
b = 14
c = -7
Your critical points are then (x2 , f(x2)) and (x1 , f(x1))