Michael J. answered 04/21/17
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In order for the quadratic equation to have at least one solution, the discriminant must be greater than or equal to zero.
b2 ≥ 4mc
where:
m = a
b = -2(a - 3)
c = a - 13
Plug in these values into the discriminant.
(-2(a - 3))2 ≥ 4a(a - 13)
(-2a + 6)(-2a + 6) ≥ 4a2 - 52a
4a2 - 24a + 36 ≥ 4a2 - 52a
Move all terms to the left side.
28a + 36 ≥ 0
28a ≥ -36
a ≥ -1.28
The value of a is all whole numbers greater than or equal to -1.28.