Sun
The line intersects the cubic at y=-2,0,2 so the area bounded by the two curves =∫(3y-y3+y)dy from y=-2 to y=2 which is 2*(2y2-y4/4) from 0 to 2 =2*(8-4)=8. So the area is 8 sq units.
Jim
Sun K.
asked 03/23/14
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Sun K.
03/23/14