
Liz S.
asked 04/17/17find g(a+1) when g(x) =1/3x-4
the 1/3 is a fraction
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1 Expert Answer
If g(x) = 1/(3x-4), then g(a+1) = 1/[3(a+1)-4] = 1/[3a+3-4] = 1/(3a-1).
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Kenneth S.
04/17/17