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Can you answer this calculus question?

Let f(x)=sin(x^2)+cos x. 
 
cos (x)=1-(x^2)/2!+(x^4)/4!-(x^6)/6!+...
 
sin(x^2)=x^2-(x^6)/3!+(x^10)/5!-(x^14)/7!+...
 
Use the series for cos (x) and the series for sin(x^2) to write the first four nonzero terms of the Taylor series for f about x=0. 
 
Answer: f(x)=1+(x^2)/2+(x^4)/4!-(121x^6)/6!+...
 
Please show all your work and accurate answer. Thanks.
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