f(x)=(x-3)2 - 49
The roots occur when f(x) = 0:
0 = (x-3)2 - 49
49 = (x-3)2
√49 = √(x-3)2
±7 = x - 3
3 ± 7 = x
x= 10 and x = -4
John D.
asked • 04/09/17how do i solve this question algebratically to find the zeros/roots/solution/x-intercept
f(x)=(x-3)2-49
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