Let a=x^2+4. Use a to find the solutions for the following equation:(x^2+4)^2+32=12x^2+48

Question

^2 means the exponent

Answer 1

a= x² +4

 

(x² +4)² +32=12(x² +4)

 

a² +32 =12a

a² -12a+32=0

(a-8)(a-4)=0

a-8=0   or a-4=0

a= 8    or   a=4

x² +4 =8     or x² +4=4

x² =4         or x² =0

x= 2 or -2 or 0

Check answer by substituting x values in eq.