
Steve S. answered 03/20/14
Tutor
5
(3)
Tutoring in Precalculus, Trig, and Differential Calculus
x = 2 - y = f(y)
x = y^2 = g(y) [parabola opening to the right]
Intersections:
2 - y = y^2
y^2 + y - 2 = 0
(y+2)(y-1) = 0
y = -2,1
A = integral{-2,1}[(f(y)-g(y)) dy]
You should be able to take it from here, Sun.
x = y^2 = g(y) [parabola opening to the right]
Intersections:
2 - y = y^2
y^2 + y - 2 = 0
(y+2)(y-1) = 0
y = -2,1
A = integral{-2,1}[(f(y)-g(y)) dy]
You should be able to take it from here, Sun.
Sun K.
03/20/14