1. y = x + 9/3
x = y + 9/3
y = x - 9/3
f-1(x) = x - 9/3
You do # 2.
1. y = (x + 2)2 - 5
x = (y + 2)2 - 5
x + 5 = (y + 2)2
√(x + 5) = y + 2
y = √(x + 5) - 2
f-1(x) = √(x + 5) - 2
The domain and range of f(x) = all real numbers.
In the inverse, we can't take the square root of a negative number, so...
x + 5 ≥ 0
x ≥ -5
The range of f-1(x) = all real numbers
You do # 2.