
Kenneth S. answered 04/05/17
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Expert Help in Algebra/Trig/(Pre)calculus to Guarantee Success in 2018
The # of ways of choosing a 3 person team, from 15 possible players, is 15C3.
If you are to be chosen along with two random others, that's 1•14C2 possible ways for that event.
P(you're on the 3 person team) = 14C2 ÷ 15C3. You may calculate this yourself.