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how can i solve cos^2-sin^2=2cos-1

im not sure which identities to use and how to prove it.

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Chen Jang T. | MaCT (Math and Chemistry Tutor)MaCT (Math and Chemistry Tutor)
4.9 4.9 (46 lesson ratings) (46)
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You need to put complete question; you missed to in lure the variable x's in your question. 
 
The most common trig identity is sin^2(x) + cos^2(x) = 1. Try using that. 
Steve S. | Tutoring in Precalculus, Trig, and Differential CalculusTutoring in Precalculus, Trig, and Diffe...
5.0 5.0 (3 lesson ratings) (3)
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Solve: cos^2(θ) - sin^2(θ) = 2cos(θ) - 1

cos^2(θ) + sin^2(θ) = 1 [Pythagorean Identity]

sin^2(θ) = 1 - cos^2(θ)

Substitute in equation to solve:

cos^2(θ) - (1 - cos^2(θ)) = 2cos(θ) - 1

2cos^2(θ) - 1 = 2cos(θ) - 1

2cos^2(θ) = 2cos(θ)

cos^2(θ) – cos(θ) = 0

cos(θ)(cos(θ) – 1) = 0

Use Zero Product Property:

cos(θ) = 0 or cos(θ) = 1

θ = pi/2 + 2n pi, n integer

θ = 3 pi/2 + 2n pi, n integer

θ = 0 + 2n pi, n integer