
Arturo O. answered 03/28/17
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Use these properties of determinants of products of square matrices of the same order:
det(AB) = det(A)det(B)
det(A-1) = 1/det(A)
det(cA)=cndet(A) for a scalar c and an n×n matrix
det[A3 * det(B-1)] = ?
Note that det(B-1) is just a scalar, which in this problem is 1/3
Then
det[A3 * det(B-1)] = det[(1/3)A3] = (1/3)4 det(A3) = (1/3)4 [det(A)]3 = (1/3)4 (-2)3
You can finish from here.