
Kenneth S. answered 03/19/17
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Calculus will seem easy if you have the right tutor!
f(x) = x + 1/x ... function to be maximized, for x < 0.
f'(x) = 1 - x-2; setting this to zero means 1 = 1/x2 and thus x = -1.
f"(x) = 2/x3 which is always negative (for negative x) and so this reveals downward concavity of f and thus substantiates that this is a maximum: f(-1) = 0