Kayla,
When you submit a problem, you'd be doing everyone a favor if you would parenthesize your expressions, since you can't write them as fractions.
I'm guessing that you mean (tanU1)/(tanU +1) = (1cotU)/(1+cotU) ??
if so, rephrase the relationships in terms of x and y lengths of a right triangle:
((y/x)(x/x))/((y/x)+(x/x)) = ((y/y)(x/y))/((y/y)+(x/y))
this reduces to
(yx)/(y+x) = (yx)/(y+x)
or 1=1 {{if neither of x,y = 0 and x not= y; you always have to go back in a problem like this and make sure that nothing (i.e. no single variable or expression) that was a denominator was =0, because that would be division by zero, which isn't allowed!}}
3/10/2014

Stanton D.
Comments