Kayla,

When you submit a problem, you'd be doing everyone a favor if you would parenthesize your expressions, since you can't write them as fractions.

I'm guessing that you mean (tanU-1)/(tanU +1) = (1-cotU)/(1+cotU) ??

if so, rephrase the relationships in terms of x and y lengths of a right triangle:

((y/x)-(x/x))/((y/x)+(x/x)) = ((y/y)-(x/y))/((y/y)+(x/y))

this reduces to

(y-x)/(y+x) = (y-x)/(y+x)

or 1=1 {{if neither of x,y = 0 and x not= -y; you always have to go back in a problem like this and make sure that nothing (i.e. no single variable or expression) that was a denominator was =0, because that would be division by zero, which isn't allowed!}}

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