
Andrew M. answered 02/24/17
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
There are 18 arrangements:
WVZXY
WVZYX
WVYZX
WVXZY
With X 1st and Y 1st you get similar
sets of 4 possibilities each so 8 more
Putting Z in place 1 and V in place 2
gives us W,X,Y to occupy the last
3 spaces with no restrictions on their
placements therein. This results in
6 possible arrangements with Z in
place 1 and V in place 2
ZVWXY
ZVWYX
ZVXWY
ZVXYW
ZVYWX
ZVYXW
Total arrangements possible = 18