
Parviz F. answered 03/04/14
Tutor
4.8
(4)
Mathematics professor at Community Colleges
Hi Steve:
Evaluation of exponential functions can be done by using either log table of both base 10 and base e
For this case:
2199.99( 1 - 0.138) ^4 = 2199.99( 0.862) ^4 = 1214. 646128
2199. 99 * e-0.138(4) = 1266 .747783
The answer come out different with 2%
However:
Consider:
2199.99* ( 0.862) t = 2199.99 e kt
t ( ln 0.862) = kt
k = ln (0.862)
2199. 99* e^((ln0.862) * 4) = 1214.646128
Read exactly the same value, but textbook don't consider this fact, and use both bases as valid calculation.
Actually they are valid, but ln table do not use the same method as log tables .