Divide 55[x4-5x3-24x2] by 11x[x-8]

Question

Divide 55[x4-5x3-24x2] by 11x[x-8]

Answer 1

      55x²(x²-5x-24)  

= --------------------

        11x(x-8)

 

    55x²(x-8)(x+3)   

= -----------------  

     11x(x-8) 

 

   55x²(x+3)  

=---------------

         11x      

 

     55x(x+3)    

= -----------

        11   

 

= 5x(x+3)

 

 

Answer 2

Hi Shaji;

55[x⁴-5x³-24x²] by 11x[x-8]

Let's first focus on the bracketed expression in the numerator,

[x⁴-5x³-24x²]

x²(x²-5x-24)

Let's factor the parenthetical expression...

(x²-5x-24)

Hopefully, one of the resulting parenthetical expressions will be...

(x-8)

(x...)(x-8)

FIRST must be (x)(x)=x²

OUTER must be (x)(-8)=-8x

OUTER and INNER must add-up to -5x.

INNER must be (3)(x)=3x

LAST must result in -24...(-8)(3)=-24

(x+3)(x-8)

 

Original expression...

55(x⁴-5x³-24x²)/[11x(x-8)]

55x²(x²-5x-24)/[11x(x-8)]

55x²[(x+3)(x-8)]/[11x(x-8)]

The (x-8) is in the numerator and denominator.  It cancels...

x¹ is in the numerator and denominator.  It cancels...

and 55/11=5

5x(x+3)