Ushara P.
asked • 01/06/14
factorize: 1-j-2j2
1-j-2j2
Parviz F.
answered • 01/07/14
Mathematics professor at Community Colleges
1 - J - 2J^2 =
- ( 2 J ^2 + j - 1 ) =
- ( 2 J^2 + 2j - j -1 )=
- [ 2 j ( j +1) - ( j + 1 ) ] =
- ( 2 J - 1) ( j + 1) =
( -2 j +1) ( j+ 1)
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