Mark M. answered • 02/09/17
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The object hits the ground when the height, h(t), = 0.
0 = 4.9t2 + 19.6t + 67.8
Can you factor and solve for t?
Mark M.
Convert by multiplying by 10
0 = 49t2 + 196t + 678
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02/09/17
Jade G.
I just realized that I need to solve by using the quadratic formula and now I don't know what to do with the two numbers, which are -2.22 and 6.22
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02/09/17
Jade G.
I need to graph the trajector, and give the definitions for variables h and t. How do I figure out how to graph this and how do I find the definition?
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02/09/17
Mark M.
The two numbers, -2.22 and 6.22, are the times at which the object hits the ground. -2.22 does not make sense, so the object hits the ground after 6.22 seconds.
h is the height
t is the time
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02/09/17
Jade G.
How would I graph this with h being on the y-axis and t being on the x-axis?
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02/09/17
Mark M.
Yes, exactly. at t = 0, h = 67.8, at t = 6.22, h = 0.
Determine the vertex and graph.
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02/09/17
Jade G.
02/09/17