Calculus. How to integrate?

Question

Evaluate the definite integral.  The boundary is from 0 to 1/5

 

∫ 5/(√(1-25x²) dx

Answer 1

This looks like an anti-derivative of the inverse of sine.

 

F(x) = 5∫(1 / (1 - 25x²)

 

F(x) = arcsin(5x)

 

 

Now evaluate            F(1/5) - F(0).