Completing the square

Question

Is it possible to complete the square for this equation ? : y^2+x^2=2x 

 

Answer 1

y²+x²=2x

 

(x²-2x) + y² = 0

 

(x²-2x+1) + y² = 1

 

(x-1)² + (y-0)² = 1²

 

The graph is a circle centered at (1,0) with radius 1.  

Answer 2

It's possible.

 

x² - 2x = -y²

x² - 2x + 1 = 1 - y²

 

Need to go further?

 

(x - 1)² = (1 + y)(1 - y)