how would you solve 9n^2+18n+79=0?

Question

 Need help finding out howto get rid of 9 and 79 can't be divided by 9

Answer 1

Use the quadratic formula.

 

If

 

ax² + bx + c = 0,

 

then

 

x = [-b ± √(b² - 4ac)] / (2a)

 

x = n

a = 9

b = 18

c = 79

 

Substitute and evaluate.