Arnold V. answered 02/20/20
Tutor
4.9
(101)
20+ years of Calculus teaching and applications in physics
∫-22 f(x) dx + ∫25 f(x) dx - ∫-2-1 f(x) dx = [ ∫-22 f(x) dx - ∫-2-1 f(x) dx] + ∫25 f(x) dx = ∫-12 f(x) dx + ∫25 f(x) dx =
= ∫-15 f(x) dx