The zeroes of cos(x) are at the odd multiples of π/2. We need to have 5θ=(2k+1)π/2 or that θ=(2k+1)π/10, for k some integer. The smallest value of θ = π/10.
Sun K.
asked • 02/24/14Find the smallest value?
Find the smallest value of θ in the interval [0, 2pi] for which the rose r=2 cos (5θ) passes through the origin.
Answer: pi/10
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