Hannah H.

asked • 01/29/17

log problem help!!

Log11m^7-33=-20 

Mark M.

Please retype to be explicit about the base and the argument.
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01/29/17

Arturo O.

Hannah,
 
Do you mean
 
log11(m7) - 33 = -20
 
or
 
log(11m7) - 33 = -20
 
or something else?
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01/29/17

Hannah H.

I'm sorry- i meant the first one 
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01/29/17

1 Expert Answer

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Arturo O. answered • 01/29/17

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Assuming you meant
 
log11(m7) - 33 = -20
 
then
 
log11(m7) = -20 + 33 = 13
 
But
 
log11(m7) = 7 log11(m)
 
Then
 
7 log11(m) = 13
 
log11(m) = 13/7
 
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Hannah H.

Are you sure it's antilog? i am not sure how those work because I have not learned about them and I don't know how to check and make sure the answer is correct and matches -20. 
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01/29/17

Hannah H.

Actually I figured it out.
7log11m-33=-20
7log11m=13
log11m=13/7
using the definition of a log, this can be rewritten as 11^13/7=m. and it checks to -20. 
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01/29/17

Arturo O.

Yes,
 
1113/7 = m 
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01/29/17

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