Search 74,225 tutors
FIND TUTORS
Ask a question
0 0

Calculus - Continuity Problem

Tutors, please sign in to answer this question.

2 Answers

Continuity at x=q means that f(q) is defined and lim f(x) = f(q) as x→q. This means that if the function changes at a given point (here, 0 and 4), the limit as x approaches the point of change must be the same whether x is approaching from the left or right.

Thus, as x→0 (from the left), F(x) →(-B)/(-2) = B/2
Also, as x→0 (from the right), Ax + B → B, therefore, B = B/2. B = 0 is the only value such that the limits of x as it approaches zero from the left and right are the same – the condition of continuity there.
 
As x → 4 (from the left), Ax + B → 4A + B = 4A
As x → 4 (from the right), 2x2 → 32, therefore, A = 8

The answer is A = 8 and B = 0.
To make it continuous, all you need is equate consecutive formulas at their boundaries.
 
(x3 - B) / (x - 2) and Ax+B must agree at x=0.
 
You get (03 - B) / (0 - 2) = A·0+B which is B/2 = B. This implies that B=0.
 
Ax+B and 2x2 must agree at x=4.
 
You get 4A+B = 32 which becomes A = (32 - B)/4 = (32 - 0)/4 = 8.
 
You can check now that
 
F(x) = (x3 / (x-2)) if X≤0 ,
8x if 0<x≤4 ,
2x2 if x>4 
 
is continuous in it's domain.

Comments

Woodbridge Calculus tutors