Ship A has 10 more rooms than ship B, ship C has 35 fewer rooms than twice the number of ship B. The total between all 3 is 711 rooms. How many do each have

Question

Algebra word problem

Answer 1

The question says 

 

A=B+10

C=2B-35

A+B+C=711

 

Since A and C are given by their relationship to B we will put them in last equation

A+B+C=711    =>       B+10+B+2B-35=711

4B-25=711    

4B=736

B=184

=>    A=B+10=194   and  C=2B-35=333

Answer 2

Hi Rene, let A represent ship A, B represent ship B, and C represent ship C. Then

 

A + B + C = 711

 

But:

 

A = B + 10

 

And 

 

C = 2B - 35

 

Substitute:

 

(B + 10) + B + (2B - 35) = 711

 

Solve for B, and then solve for A and C.

 

Questions?